Freezing Julia Set...
Freezing Julia Set #genuary #genuary8 #winter #fractalArt #juliaset
Freezing Julia Set #genuary #genuary8 #winter #fractalArt #juliaset
Newton fractal
z - a f(z)/f'(z)
f(z) = cos(z)^1-c with c = (0,0), a = (0.7,0)
#fractalArt #mathematicalArt
#fractal #genuary #genuary6 #newtonFractal